\[\int_{{}}^{{}}{\frac{dx}{{{e}^{x}}-1}=}\] [MP PET 1989]

\[\int_{{}}^{{}}{\frac{dx}{{{e}^{x}}-1}=}\] �

1.	\[\int_{{}}^{{}}{\frac{dx}{{{e}^{x}}-1}=}\] [MP PET 1989]
A.	\[\ln (1-{{e}^{-x}})+c\]
B.	\[-\ln (1-{{e}^{-x}})+c\]
C.	\[\ln ({{e}^{x}}-1)+c\]
D.	None of these
Answer» B. \[-\ln (1-{{e}^{-x}})+c\]

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\[\int_{{}}^{{}}{\frac{dx}{{{e}^{x}}-1}=}\] [MP PET 1989]

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