1.

\[\int_{{}}^{{}}{\frac{dx}{{{e}^{x}}+1-2{{e}^{-x}}}=}\]

A.                 \[\log ({{e}^{x}}-1)-\log ({{e}^{x}}+2)+c\]            
B.                 \[\frac{1}{2}\log ({{e}^{x}}-1)-\frac{1}{3}\log ({{e}^{x}}+2)+c\]
C.                 \[\frac{1}{3}\log ({{e}^{x}}-1)-\frac{1}{3}\log ({{e}^{x}}+2)+c\]
D.                 \[\frac{1}{3}\log ({{e}^{x}}-1)+\frac{1}{3}\log ({{e}^{x}}+2)+c\]
Answer» D.                 \[\frac{1}{3}\log ({{e}^{x}}-1)+\frac{1}{3}\log ({{e}^{x}}+2)+c\]


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