\[\int{\frac{dx}{{{a}^{2}}-{{x}^{2}}}}\] is equal to [EAMCET 2002]

\[\frac{1}{2a}\log \,\left( \frac{a-x}{a+x} \right)\]

\[\frac{1}{a}{{\tan }^{-1}}\left( \frac{x}{a} \right)\]

\[\frac{1}{2a}{{\sin }^{-1}}\left( \frac{a-x}{a+x} \right)\]

\[\frac{1}{2a}\log \,\left( \frac{a+x}{a-x} \right)\]

\[\int{\frac{dx}{{{a}^{2}}-{{x}^{2}}}}\] is equal to

1.	\[\int{\frac{dx}{{{a}^{2}}-{{x}^{2}}}}\] is equal to [EAMCET 2002]
A.	\[\frac{1}{a}{{\tan }^{-1}}\left( \frac{x}{a} \right)\]
B.	\[\frac{1}{2a}{{\sin }^{-1}}\left( \frac{a-x}{a+x} \right)\]
C.	\[\frac{1}{2a}\log \,\left( \frac{a+x}{a-x} \right)\]
D.	\[\frac{1}{2a}\log \,\left( \frac{a-x}{a+x} \right)\]
Answer» D. \[\frac{1}{2a}\log \,\left( \frac{a-x}{a+x} \right)\]

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\[\int{\frac{dx}{{{a}^{2}}-{{x}^{2}}}}\] is equal to [EAMCET 2002]

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