\[\int_{{}}^{{}}{\frac{dx}{1-{{x}^{2}}}=}\] [MP PET 1987, 92, 2000]

1.	\[\int_{{}}^{{}}{\frac{dx}{1-{{x}^{2}}}=}\] [MP PET 1987, 92, 2000]
A.	\[{{\tan }^{-1}}x+c\]
B.	\[{{\sin }^{-1}}x+c\]
C.	\[\frac{1}{2}\ln \left\| \frac{1+x}{1-x} \right\|+c\]
D.	\[\frac{1}{2}\ln \left\| \frac{1-x}{1+x} \right\|+c\]
Answer» D. \[\frac{1}{2}\ln \left\| \frac{1-x}{1+x} \right\|+c\]

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\[\int_{{}}^{{}}{\frac{dx}{1-{{x}^{2}}}=}\] [MP PET 1987, 92, 2000]

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