\[\int_{{}}^{{}}{\frac{dx}{1+{{e}^{x}}}=}\] [MP PET 1991; Roorkee 1977

1.	\[\int_{{}}^{{}}{\frac{dx}{1+{{e}^{x}}}=}\] [MP PET 1991; Roorkee 1977]
A.	\[\log (1+{{e}^{x}})\]
B.	\[-\log (1+{{e}^{-x}})\]
C.	\[-\log (1-{{e}^{-x}})\]
D.	\[\log ({{e}^{-x}}+{{e}^{-2x}})\]
Answer» C. \[-\log (1-{{e}^{-x}})\]

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\[\int_{{}}^{{}}{\frac{dx}{1+{{e}^{x}}}=}\] [MP PET 1991; Roorkee 1977]

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