\[\int \frac{\cos 4x-1}{\cot x-\tan x}dx\]is equal to

1.	\[\int \frac{\cos 4x-1}{\cot x-\tan x}dx\]is equal to
A.	\[\frac{1}{2}\ln \left\| \sec 2x \right\|-\frac{1}{4}{{\cos }^{2}}2x+c\]
B.	\[\frac{1}{2}\ln \left\| \sec 2x \right\|+\frac{1}{4}{{\cos }^{2}}x+c\]
C.	\[\frac{1}{2}\ln \left\| \cos 2x \right\|-\frac{1}{4}{{\cos }^{2}}2x+c\]
D.	\[\frac{1}{2}\ln \left\| \cos 2x \right\|+\frac{1}{4}{{\cos }^{2}}x+c\]
Answer» D. \[\frac{1}{2}\ln \left\| \cos 2x \right\|+\frac{1}{4}{{\cos }^{2}}x+c\]

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\[\int \frac{\cos 4x-1}{\cot x-\tan x}dx\]is equal to

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