\[\int \frac{2\sin x}{(3+sin2x)}dx\]is equal to

1.	\[\int \frac{2\sin x}{(3+sin2x)}dx\]is equal to
A.	\[\frac{1}{2}\ln \left\| \frac{2+\sin x-\cos x}{2-\sin x+\cos x} \right\|-\frac{1}{\sqrt{2}}{{\tan }^{-1}}\left( \frac{\sin x+\cos x}{\sqrt{2}} \right)+c\]
B.	\[\frac{1}{2}\ln \left\| \frac{2+\sin x-\cos x}{2-\sin x+\cos x} \right\|-\frac{1}{2\sqrt{2}}{{\tan }^{-1}}\left( \frac{\sin x+\cos x}{\sqrt{2}} \right)+c\]
C.	\[\frac{1}{4}\ln \left\| \frac{2+\sin x-\cos x}{2-\sin x+\cos x} \right\|-\frac{1}{\sqrt{2}}{{\tan }^{-1}}\left( \frac{\sin x+\cos x}{\sqrt{2}} \right)+c\]
D.	none of these
Answer» D. none of these

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\[\int \frac{2\sin x}{(3+sin2x)}dx\]is equal to

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