\[\int_{{}}^{{}}{\frac{1}{x\sqrt{{{x}^{2}}-1}}\ dx=}\] [MP PET 1988]

1.	\[\int_{{}}^{{}}{\frac{1}{x\sqrt{{{x}^{2}}-1}}\ dx=}\] [MP PET 1988]
A.	\[{{\cos }^{-1}}x+c\]
B.	\[{{\sec }^{-1}}x+c\]
C.	\[{{\cot }^{-1}}x+c\]
D.	\[{{\tan }^{-1}}x+c\]
Answer» C. \[{{\cot }^{-1}}x+c\]

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\[\int_{{}}^{{}}{\frac{1}{x\sqrt{{{x}^{2}}-1}}\ dx=}\] [MP PET 1988]

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