\[\int_{{}}^{{}}{\frac{1}{(x-1)({{x}^{2}}+1)}dx}=\] [Roorkee 1984

1.	\[\int_{{}}^{{}}{\frac{1}{(x-1)({{x}^{2}}+1)}dx}=\] [Roorkee 1984]
A.	\[\frac{1}{2}\log (x-1)-\frac{1}{4}\log ({{x}^{2}}+1)-\frac{1}{2}{{\tan }^{-1}}x+c\]
B.	\[\frac{1}{2}\log (x-1)+\frac{1}{4}\log ({{x}^{2}}+1)-\frac{1}{2}{{\tan }^{-1}}x+c\]
C.	\[\frac{1}{2}\log (x-1)-\frac{1}{2}\log ({{x}^{2}}+1)-\frac{1}{2}{{\tan }^{-1}}x+c\]
D.	None of these
Answer» B. \[\frac{1}{2}\log (x-1)+\frac{1}{4}\log ({{x}^{2}}+1)-\frac{1}{2}{{\tan }^{-1}}x+c\]

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\[\int_{{}}^{{}}{\frac{1}{(x-1)({{x}^{2}}+1)}dx}=\] [Roorkee 1984]

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