\[\int_{{}}^{{}}{\frac{1}{{{[{{(x-1)}^{3}}{{(x+2)}^{5}}]}^{1/4}}}\ dx}\] is equal to

\[\frac{4}{3}{{\left( \frac{x+2}{x-1} \right)}^{1/4}}+c\]

\[\frac{4}{3}{{\left( \frac{x-1}{x+2} \right)}^{1/4}}+c\]

\[\frac{4}{3}{{\left( \frac{x+2}{x-1} \right)}^{1/4}}+c\]

\[\frac{1}{3}{{\left( \frac{x-1}{x+2} \right)}^{1/4}}+c\]

\[\frac{1}{3}{{\left( \frac{x+2}{x-1} \right)}^{1/4}}+c\]

\[\int_{{}}^{{}}{\frac{1}{{{[{{(x-1)}^{3}}{{(x+2)}^{5}}]}^{1/4}}}\ dx}

1.	\[\int_{{}}^{{}}{\frac{1}{{{[{{(x-1)}^{3}}{{(x+2)}^{5}}]}^{1/4}}}\ dx}\] is equal to
A.	\[\frac{4}{3}{{\left( \frac{x-1}{x+2} \right)}^{1/4}}+c\]
B.	\[\frac{4}{3}{{\left( \frac{x+2}{x-1} \right)}^{1/4}}+c\]
C.	\[\frac{1}{3}{{\left( \frac{x-1}{x+2} \right)}^{1/4}}+c\]
D.	\[\frac{1}{3}{{\left( \frac{x+2}{x-1} \right)}^{1/4}}+c\]
Answer» B. \[\frac{4}{3}{{\left( \frac{x+2}{x-1} \right)}^{1/4}}+c\]

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\[\int_{{}}^{{}}{\frac{1}{{{[{{(x-1)}^{3}}{{(x+2)}^{5}}]}^{1/4}}}\ dx}\] is equal to

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