\[\int_{{}}^{{}}{\frac{1}{{{\cos }^{2}}x{{(1-\tan x)}^{2}}}dx=}\]

1.	\[\int_{{}}^{{}}{\frac{1}{{{\cos }^{2}}x{{(1-\tan x)}^{2}}}dx=}\]
A.	\[\frac{1}{\tan x-1}+c\]
B.	\[\frac{1}{1-\tan x}+c\]
C.	\[-\frac{1}{3}\frac{1}{{{(1-\tan x)}^{3}}}+c\]
D.	None of these
Answer» C. \[-\frac{1}{3}\frac{1}{{{(1-\tan x)}^{3}}}+c\]

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\[\int_{{}}^{{}}{\frac{1}{{{\cos }^{2}}x{{(1-\tan x)}^{2}}}dx=}\]

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