\[\int_{{}}^{{}}{\frac{1}{{{\cos }^{-1}}x.\sqrt{1-{{x}^{2}}}}dx=}\]

1.	\[\int_{{}}^{{}}{\frac{1}{{{\cos }^{-1}}x.\sqrt{1-{{x}^{2}}}}dx=}\]
A.	\[\log ({{\cos }^{-1}}x)+c\]
B.	\[-\log ({{\cos }^{-1}}x)+c\]
C.	\[-\frac{1}{2{{({{\cos }^{-1}}x)}^{2}}}+c\]
D.	None of these
Answer» C. \[-\frac{1}{2{{({{\cos }^{-1}}x)}^{2}}}+c\]

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\[\int_{{}}^{{}}{\frac{1}{{{\cos }^{-1}}x.\sqrt{1-{{x}^{2}}}}dx=}\]

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