\[\int_{{}}^{{}}{\frac{1}{1+{{\sin }^{2}}x}\ dx=}\]

1.	\[\int_{{}}^{{}}{\frac{1}{1+{{\sin }^{2}}x}\ dx=}\]
A.	\[\frac{1}{\sqrt{2}}{{\tan }^{-1}}(\sqrt{2}\tan x)+k\]
B.	\[\sqrt{2}{{\tan }^{-1}}(\sqrt{2}\tan x)+k\]
C.	\[-\frac{1}{\sqrt{2}}{{\tan }^{-1}}(\sqrt{2}\tan x)+k\]
D.	\[-\sqrt{2}{{\tan }^{-1}}(\sqrt{2}\tan x)+k\]
Answer» B. \[\sqrt{2}{{\tan }^{-1}}(\sqrt{2}\tan x)+k\]

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\[\int_{{}}^{{}}{\frac{1}{1+{{\sin }^{2}}x}\ dx=}\]

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