\[\int_{{}}^{{}}{{{e}^{x}}\left[ {{\sin }^{-1}}\frac{x}{a}+\frac{1}{\sqrt{{{a}^{2}}-{{x}^{2}}}} \right]dx=}\]

\[\frac{{{e}^{x}}}{\sqrt{{{a}^{2}}-{{x}^{2}}}}+c\]

\[\frac{1}{a}{{e}^{x}}{{\sin }^{-1}}\frac{x}{a}+c\]

\[a{{e}^{x}}{{\sin }^{-1}}\frac{x}{a}+c\]

\[{{e}^{x}}{{\sin }^{-1}}\frac{x}{a}+c\]

\[\int_{{}}^{{}}{{{e}^{x}}\left[ {{\sin }^{-1}}\frac{x}{a}+\frac{1}{\s

1.	\[\int_{{}}^{{}}{{{e}^{x}}\left[ {{\sin }^{-1}}\frac{x}{a}+\frac{1}{\sqrt{{{a}^{2}}-{{x}^{2}}}} \right]dx=}\]
A.	\[\frac{1}{a}{{e}^{x}}{{\sin }^{-1}}\frac{x}{a}+c\]
B.	\[a{{e}^{x}}{{\sin }^{-1}}\frac{x}{a}+c\]
C.	\[{{e}^{x}}{{\sin }^{-1}}\frac{x}{a}+c\]
D.	\[\frac{{{e}^{x}}}{\sqrt{{{a}^{2}}-{{x}^{2}}}}+c\]
Answer» D. \[\frac{{{e}^{x}}}{\sqrt{{{a}^{2}}-{{x}^{2}}}}+c\]

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\[\int_{{}}^{{}}{{{e}^{x}}\left[ {{\sin }^{-1}}\frac{x}{a}+\frac{1}{\sqrt{{{a}^{2}}-{{x}^{2}}}} \right]dx=}\]

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