\[\int_{{}}^{{}}{{{e}^{\sqrt{x}}}\ dx}\] is equal to [MP PET 1998]

\[2(\sqrt{x}+1){{e}^{\sqrt{x}}}+A\] (A is an arbitrary constant)

\[\frac{1}{2}{{e}^{\sqrt{x}}}+A\]

\[2(\sqrt{x}-1){{e}^{\sqrt{x}}}+A\]

\[\int_{{}}^{{}}{{{e}^{\sqrt{x}}}\ dx}\] is equal to �

1.	\[\int_{{}}^{{}}{{{e}^{\sqrt{x}}}\ dx}\] is equal to [MP PET 1998]
A.	\[{{e}^{\sqrt{x}}}+A\]
B.	\[\frac{1}{2}{{e}^{\sqrt{x}}}+A\]
C.	\[2(\sqrt{x}-1){{e}^{\sqrt{x}}}+A\]
D.	\[2(\sqrt{x}+1){{e}^{\sqrt{x}}}+A\] (A is an arbitrary constant)
Answer» D. \[2(\sqrt{x}+1){{e}^{\sqrt{x}}}+A\] (A is an arbitrary constant)

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\[\int_{{}}^{{}}{{{e}^{\sqrt{x}}}\ dx}\] is equal to [MP PET 1998]

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