\[\int_{{}}^{{}}{{{e}^{-2x}}\sin 3x\ dx=}\] – McqOptions

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1.	\[\int_{{}}^{{}}{{{e}^{-2x}}\sin 3x\ dx=}\]
A.	\[\frac{1}{13}{{e}^{-2x}}[\sin 3x+\cos 3x]+c\]
B.	\[-\frac{1}{13}{{e}^{-2x}}[\sin 3x+\cos 3x]+c\]
C.	\[\frac{1}{13}{{e}^{-2x}}[2\sin 3x+3\cos 3x]+c\]
D.	\[-\frac{1}{13}{{e}^{-2x}}[2\sin 3x+3\cos 3x]+c\]
Answer» E.

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