\[\int_{{}}^{{}}{{{e}^{2x+\log x}}}dx=\]

1.	\[\int_{{}}^{{}}{{{e}^{2x+\log x}}}dx=\]
A.	\[\frac{1}{4}(2x-1)+\frac{2}{x+1}+c\]
B.	\[\frac{1}{4}(2x+1)+\frac{2}{x+1}+c\]
C.	\[\frac{1}{2}(2x+1){{e}^{2x}}+c\]
D.	\[\frac{1}{2}(2x+1){{e}^{2x}}+c\]
Answer» B. \[\frac{1}{4}(2x+1)+\frac{2}{x+1}+c\]

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\[\int_{{}}^{{}}{{{e}^{2x+\log x}}}dx=\]

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