\[\int_{{}}^{{}}{{{e}^{2x}}\frac{1+\sin 2x}{1+\cos 2x}}\ dx=\]

1.	\[\int_{{}}^{{}}{{{e}^{2x}}\frac{1+\sin 2x}{1+\cos 2x}}\ dx=\]
A.	\[{{e}^{2x}}\tan x+c\]
B.	\[{{e}^{2x}}\cot x+c\]
C.	\[\frac{{{e}^{2x}}\tan x}{2}+c\]
D.	\[\frac{{{e}^{2x}}\cot x}{2}+c\]
Answer» D. \[\frac{{{e}^{2x}}\cot x}{2}+c\]

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\[\int_{{}}^{{}}{{{e}^{2x}}\frac{1+\sin 2x}{1+\cos 2x}}\ dx=\]

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