\[\int_{{}}^{{}}{{{\cos }^{3}}x\ {{e}^{\log (\sin x)}}}\ dx\] is equal to

\[-\frac{{{\sin }^{4}}x}{4}+c\]

\[-\frac{{{\cos }^{4}}x}{4}+c\]

\[\int_{{}}^{{}}{{{\cos }^{3}}x\ {{e}^{\log (\sin x)}}}\ dx\] is equal

1.	\[\int_{{}}^{{}}{{{\cos }^{3}}x\ {{e}^{\log (\sin x)}}}\ dx\] is equal to
A.	\[-\frac{{{\sin }^{4}}x}{4}+c\]
B.	\[-\frac{{{\cos }^{4}}x}{4}+c\]
C.	\[\frac{{{e}^{\sin x}}}{4}+c\]
D.	None of these
Answer» C. \[\frac{{{e}^{\sin x}}}{4}+c\]

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\[\int_{{}}^{{}}{{{\cos }^{3}}x\ {{e}^{\log (\sin x)}}}\ dx\] is equal to

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