\[\int_{1}^{\sqrt{3}}{\frac{1}{1+{{x}^{2}}}dx}\] is equal to [DCE 2002]

\[\int_{1}^{\sqrt{3}}{\frac{1}{1+{{x}^{2}}}dx}\] is equal to �

1.	\[\int_{1}^{\sqrt{3}}{\frac{1}{1+{{x}^{2}}}dx}\] is equal to [DCE 2002]
A.	\[\pi /12\]
B.	\[\pi /6\]
C.	\[\pi /4\]
D.	\[\pi /3\]
Answer» B. \[\pi /6\]

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\[\int_{1}^{\sqrt{3}}{\frac{1}{1+{{x}^{2}}}dx}\] is equal to [DCE 2002]

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