\[\int_{1}^{e}{\frac{{{e}^{x}}}{x}(1+x\log x)\,dx}=\]

1.	\[\int_{1}^{e}{\frac{{{e}^{x}}}{x}(1+x\log x)\,dx}=\]
A.	\[{{e}^{e}}\]
B.	\[{{e}^{e}}-e\]
C.	\[{{e}^{e}}+e\]
D.	None of these
Answer» B. \[{{e}^{e}}-e\]

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\[\int_{1}^{e}{\frac{{{e}^{x}}}{x}(1+x\log x)\,dx}=\]

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