\[\int_{1}^{2}{\frac{1}{{{x}^{2}}}{{e}^{\frac{-1}{x}}}\,dx=}\] [DCE 2001]

\[\int_{1}^{2}{\frac{1}{{{x}^{2}}}{{e}^{\frac{-1}{x}}}\,dx=}\]

1.	\[\int_{1}^{2}{\frac{1}{{{x}^{2}}}{{e}^{\frac{-1}{x}}}\,dx=}\] [DCE 2001]
A.	\[\sqrt{e}+1\]
B.	\[\sqrt{e}-1\]
C.	\[\frac{\sqrt{e}+1}{e}\]
D.	\[\frac{\sqrt{e}-1}{e}\]
Answer» E.

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\[\int_{1}^{2}{\frac{1}{{{x}^{2}}}{{e}^{\frac{-1}{x}}}\,dx=}\] [DCE 2001]

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