\[\int_{-1}^{1}{{{\sin }^{11}}x\,dx}\] is equal to [MNR 1995]

\[\frac{10}{11}.\frac{8}{9}.\frac{6}{7}.\frac{4}{5}.\frac{2}{3}\]

\[\frac{10}{11}.\frac{8}{9}.\frac{6}{7}.\frac{4}{5}.\frac{2}{3}.\frac{\pi }{2}\]

\[\int_{-1}^{1}{{{\sin }^{11}}x\,dx}\] is equal to

1.	\[\int_{-1}^{1}{{{\sin }^{11}}x\,dx}\] is equal to [MNR 1995]
A.	\[\frac{10}{11}.\frac{8}{9}.\frac{6}{7}.\frac{4}{5}.\frac{2}{3}\]
B.	\[\frac{10}{11}.\frac{8}{9}.\frac{6}{7}.\frac{4}{5}.\frac{2}{3}.\frac{\pi }{2}\]
C.	1
D.	0
Answer» E.

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\[\int_{-1}^{1}{{{\sin }^{11}}x\,dx}\] is equal to [MNR 1995]

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