\[\int_{0}^{\pi }{\frac{dx}{1+\sin x}}=\] [CEE 1993]

\[\int_{0}^{\pi }{\frac{dx}{1+\sin x}}=\] �

1.	\[\int_{0}^{\pi }{\frac{dx}{1+\sin x}}=\] [CEE 1993]
A.	0
B.	\[\frac{1}{2}\]
C.	2
D.	\[\frac{3}{2}\]
Answer» D. \[\frac{3}{2}\]

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\[\int_{0}^{\pi }{\frac{dx}{1+\sin x}}=\] [CEE 1993]

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