\[\int_{0}^{\pi /2}{\frac{dx}{2+\cos x}}=\] [BIT Ranchi 1992]

\[2\sqrt{3}{{\tan }^{-1}}\left( \sqrt{3} \right)\]

\[\frac{1}{\sqrt{3}}{{\tan }^{-1}}\left( \frac{1}{\sqrt{3}} \right)\]

\[\sqrt{3}{{\tan }^{-1}}\left( \sqrt{3} \right)\]

\[\frac{2}{\sqrt{3}}{{\tan }^{-1}}\left( \frac{1}{\sqrt{3}} \right)\]

\[\int_{0}^{\pi /2}{\frac{dx}{2+\cos x}}=\] �

1.	\[\int_{0}^{\pi /2}{\frac{dx}{2+\cos x}}=\] [BIT Ranchi 1992]
A.	\[\frac{1}{\sqrt{3}}{{\tan }^{-1}}\left( \frac{1}{\sqrt{3}} \right)\]
B.	\[\sqrt{3}{{\tan }^{-1}}\left( \sqrt{3} \right)\]
C.	\[\frac{2}{\sqrt{3}}{{\tan }^{-1}}\left( \frac{1}{\sqrt{3}} \right)\]
D.	\[2\sqrt{3}{{\tan }^{-1}}\left( \sqrt{3} \right)\]
Answer» D. \[2\sqrt{3}{{\tan }^{-1}}\left( \sqrt{3} \right)\]

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\[\int_{0}^{\pi /2}{\frac{dx}{2+\cos x}}=\] [BIT Ranchi 1992]

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