\[\int_{0}^{a}{\frac{{{x}^{4}}\,dx}{{{({{a}^{2}}+{{x}^{2}})}^{4}}}}=\]

1.	\[\int_{0}^{a}{\frac{{{x}^{4}}\,dx}{{{({{a}^{2}}+{{x}^{2}})}^{4}}}}=\]
A.	\[\frac{1}{16{{a}^{3}}}\left( \frac{\pi }{4}-\frac{1}{3} \right)\]
B.	\[\frac{1}{16{{a}^{3}}}\left( \frac{\pi }{4}+\frac{1}{3} \right)\]
C.	\[\frac{1}{16}{{a}^{3}}\left( \frac{\pi }{4}-\frac{1}{3} \right)\]
D.	\[\frac{1}{16}{{a}^{3}}\left( \frac{\pi }{4}+\frac{1}{3} \right)\]
Answer» B. \[\frac{1}{16{{a}^{3}}}\left( \frac{\pi }{4}+\frac{1}{3} \right)\]

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\[\int_{0}^{a}{\frac{{{x}^{4}}\,dx}{{{({{a}^{2}}+{{x}^{2}})}^{4}}}}=\]

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