\[\int_{0}^{2\pi }{\frac{\sin 2\theta }{a-b\,\cos \theta }\,d\theta =}\] [Roorkee 1988]

\[\int_{0}^{2\pi }{\frac{\sin 2\theta }{a-b\,\cos \theta }\,d\theta =}

1.	\[\int_{0}^{2\pi }{\frac{\sin 2\theta }{a-b\,\cos \theta }\,d\theta =}\] [Roorkee 1988]
A.	1
B.	2
C.	\[\frac{\pi }{4}\]
D.	0
Answer» E.

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\[\int_{0}^{2\pi }{\frac{\sin 2\theta }{a-b\,\cos \theta }\,d\theta =}\] [Roorkee 1988]

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