\[\int_{0}^{1}{[f(x)g''(x)-f''(x)g(x)]dx}\] is equal to: [Given f(0) = g (0) = 0]

\[\int_{0}^{1}{[f(x)g''(x)-f''(x)g(x)]dx}\] is equal to: [Given f(0) =

1.	\[\int_{0}^{1}{[f(x)g''(x)-f''(x)g(x)]dx}\] is equal to: [Given f(0) = g (0) = 0]
A.	\[f(1)g(1)-f(1)g'(1)\]
B.	\[f(1)g'(1)+f'(1)g(1)\]
C.	\[f(1)g'(1)-f'(1)g(1)\]
D.	None of these
Answer» D. None of these

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\[\int_{0}^{1}{[f(x)g''(x)-f''(x)g(x)]dx}\] is equal to: [Given f(0) = g (0) = 0]

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