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1. |
In Young's double slit experiment, the distance between the two slits is 0.1 mm and the wavelength of light used is \[4\times {{10}^{-7}}m\]. If the width of the fringe on the screen is 4 mm, the distance between screen and slit is [Bihar CMEET 1995] |
A. | 0.1 mm |
B. | 1 cm |
C. | 0.1 cm |
D. | 1 m |
Answer» E. | |