In under damped vibrating system, if x‚Äö√á√Ö and x‚Äö√á√á are the successive values of the amplitude on the same side of the mean position, then the logarithmic decrement is equal to$

loge(x‚Äö√á√Ö/x‚Äö√á√á)

x‚Äö√á√Ö/x‚Äö√á√á

log(x‚Äö√á√Ö/x‚Äö√á√á)

log(x‚Äö√á√Ö.x‚Äö√á√á)

In under damped vibrating system, if x‚Äö√á√Ö and x‚Äö�

1.	In under damped vibrating system, if x‚Äö√á√Ö and x‚Äö√á√á are the successive values of the amplitude on the same side of the mean position, then the logarithmic decrement is equal to$
A.	x‚Äö√á√Ö/x‚Äö√á√á
B.	log(x‚Äö√á√Ö/x‚Äö√á√á)
C.	loge(x‚Äö√á√Ö/x‚Äö√á√á)
D.	log(x‚Äö√á√Ö.x‚Äö√á√á)
Answer» C. loge(x‚Äö√á√Ö/x‚Äö√á√á)

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In under damped vibrating system, if x‚Äö√á√Ö and x‚Äö√á√á are the successive values of the amplitude on the same side of the mean position, then the logarithmic decrement is equal to$

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