MCQOPTIONS
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| 1. |
In the visible region of the spectrum the rotation of the place of polarization is given by \[\theta =a+\frac{b}{{{\lambda }^{2}}}\]. The optical rotation produced by a particular material is found to be 30° per mm at \[\lambda =5000\]Å and 50° per mm at \[\lambda =4000\text{{ }\!\!\mathrm{\AA}\!\!\text{ }}\]. The value of constant a will be |
| A. | \[+\frac{50{}^\circ }{9}\]per mm |
| B. | \[-\frac{50{}^\circ }{9}\]per mm |
| C. | \[+\frac{9{}^\circ }{50}\]per mm |
| D. | \[-\frac{9{}^\circ }{50}\]per mm |
| Answer» C. \[+\frac{9{}^\circ }{50}\]per mm | |