1.

In the triangle ABC, \[\overrightarrow{AB}=\mathbf{a},\,\,\overrightarrow{AC}=\mathbf{c},\,\,\overrightarrow{BC}=\mathbf{b}\], then                                                                                 [RPET 1984]

A. \[\mathbf{a}+\mathbf{b}+\mathbf{c}=\mathbf{0}\]    
B. \[\mathbf{a}+\mathbf{b}-\mathbf{c}=\mathbf{0}\]
C. \[\mathbf{a}-\mathbf{b}+\mathbf{c}=\mathbf{0}\]      
D. \[-\,\mathbf{a}+\mathbf{b}+\mathbf{c}=\mathbf{0}\]
Answer» C. \[\mathbf{a}-\mathbf{b}+\mathbf{c}=\mathbf{0}\]      


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