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1. |
In the series of reaction \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\underset{0-5{}^\circ C}{\mathop{\xrightarrow{NaN{{O}_{2}}/HCl}}}\,X\underset{C{{H}_{2}}O}{\mathop{\xrightarrow{HN{{O}_{2}}}}}\,Y+{{N}_{2}}+HCl\] X and Y are respectively [EAMCET 2003] |
A. | \[{{C}_{6}}{{H}_{5}}-N=N-{{C}_{6}}{{H}_{5}}\,,\,{{C}_{6}}{{H}_{5}}N_{2}^{\oplus }C{{l}^{\Theta }}\] |
B. | \[{{C}_{6}}{{H}_{5}}N_{2}^{\oplus }C{{l}^{\Theta }},\,{{C}_{6}}{{H}_{5}}-N=N-{{C}_{6}}{{H}_{5}}\] |
C. | \[{{C}_{6}}{{H}_{5}}N_{2}^{\oplus }C{{l}^{\Theta }},\,{{C}_{6}}{{H}_{5}}N{{O}_{2}}\] |
D. | \[{{C}_{6}}{{H}_{5}}N{{O}_{2}},\,{{C}_{6}}{{H}_{6}}\] |
Answer» D. \[{{C}_{6}}{{H}_{5}}N{{O}_{2}},\,{{C}_{6}}{{H}_{6}}\] | |