1.

In the reaction, \[{{C}_{6}}{{H}_{5}}OH\xrightarrow{NaOH}(A)\] \[\underset{140{}^\circ C,\ (4-7\,atm)}{\mathop{\xrightarrow{\ C{{O}_{2}}\ \ \ \ \ \ \ \ \ \ \ \ }}}\,(B)\] \[\xrightarrow{HCl}(C),\]the compound  is                          [Pb. CET 2001]

A.                 Benzoic acid      
B.                 Salicylaldehyde
C.                 Chlorobenzene                
D.                 Salicylic acid
Answer» E.


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