MCQOPTIONS
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| 1. |
In the reaction, \[{{C}_{6}}{{H}_{5}}OH\xrightarrow{NaOH}(A)\] \[\underset{140{}^\circ C,\ (4-7\,atm)}{\mathop{\xrightarrow{\ C{{O}_{2}}\ \ \ \ \ \ \ \ \ \ \ \ }}}\,(B)\] \[\xrightarrow{HCl}(C),\]the compound is [Pb. CET 2001] |
| A. | Benzoic acid |
| B. | Salicylaldehyde |
| C. | Chlorobenzene |
| D. | Salicylic acid |
| Answer» E. | |