In the reaction, \[2KMn{{O}_{4}}+16HCl\to 5C{{l}_{2}}+2MnC{{l}_{2}}+2KCl+8{{H}_{2}}O\] the reduction product is [Kerala (Med.) 2003]

In the reaction, \[2KMn{{O}_{4}}+16HCl\to 5C{{l}_{2}}+2MnC{{l}_{2}}+2K

1.	In the reaction, \[2KMn{{O}_{4}}+16HCl\to 5C{{l}_{2}}+2MnC{{l}_{2}}+2KCl+8{{H}_{2}}O\] the reduction product is [Kerala (Med.) 2003]
A.	\[C{{l}_{2}}\]
B.	\[MnC{{l}_{2}}\]
C.	\[{{H}_{2}}O\]
D.	\[KCl\]
Answer» C. \[{{H}_{2}}O\]

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In the reaction, \[2KMn{{O}_{4}}+16HCl\to 5C{{l}_{2}}+2MnC{{l}_{2}}+2KCl+8{{H}_{2}}O\] the reduction product is [Kerala (Med.) 2003]

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