In the reaction \[_{1}^{2}H+_{1}^{3}H\to _{2}^{4}He+_{0}^{1}n\]. If the tending energies of \[_{1}^{2}H,\text{ }_{1}^{3}H\text{ and }_{2}^{4}He\] are respectively \[a,\text{ b and }c\] (in MeV), then the energy (in MeV) released in this reaction is [CBSE PMT 2005]

• A.            \[c+a-b\]                               
• B.            \[c-a-b\]
• C.            \[a+b+c\]                              
• D.            \[a+b-c\]