1.

In the reaction \[_{1}^{2}H+_{1}^{3}H\to _{2}^{4}He+_{0}^{1}n\]. If the tending energies of \[_{1}^{2}H,\text{ }_{1}^{3}H\text{ and }_{2}^{4}He\] are respectively \[a,\text{ b and }c\] (in MeV), then the energy (in MeV) released in this reaction is

A. \[c+a-b\]
B. \[c-a-b\]
C. \[a+b+c\]
D. \[a+b-c\]
Answer» C. \[a+b+c\]


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