1.

In the given nuclear reaction A, B, C, D, E represents \[_{92}{{U}^{238}}{{\xrightarrow{\alpha }}_{B}}T{{h}^{A}}{{\xrightarrow{\beta }}_{D}}P{{a}^{C}}{{\xrightarrow{E}}_{92}}{{U}^{234}}\]

A. A = 234, B = 90, C = 234, D = 91, E = \[\beta \]
B. A = 234, B = 90, C = 238, D = 94, E = \[\alpha \]
C. A = 238, B = 93, C = 234, D = 91, E = \[\beta \]
D. A = 234, B = 90, C = 234, D = 93, E = \[\alpha \]
Answer» B. A = 234, B = 90, C = 238, D = 94, E = \[\alpha \]


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