In the given matrix $\left[ {\begin{array}{*{20}{c}} 1&{ - 1}&2\ 0&1&0\ 1&2&1 \end{array}} \right]$, one of the eigenvalues is 1. The eigenvectors corresponding to the eigenvalue 1 are

Question

TuteeHUB · Accepted Answer

$\left\{ {\alpha \left( {\sqrt 2 0,\;1} \right){\rm{|}}\alpha \; \ne \;0,\;\alpha \in } \mathbb{R} \right\}$

TuteeHUB · Answer

{(4, 2, 1)|𝛼 ≠ 0, 𝛼 ∈ ℝ}

TuteeHUB · Answer

{(−4, 2, 1)|𝛼 ≠ 0, 𝛼∈ℝ}

TuteeHUB · Answer

$$\left\{ {\alpha \left( { - \sqrt 2 ,\;0,\;1} \right)|\alpha \; \ne \;0,\;\alpha \epsilon \mathbb{R} } \right\}\;$$

1.	In the given matrix \(\left[ {\begin{array}{*{20}{c}} 1&{ - 1}&2\\ 0&1&0\\ 1&2&1 \end{array}} \right]\), one of the eigenvalues is 1. The eigenvectors corresponding to the eigenvalue 1 are
A.	{(4, 2, 1)\|𝛼 ≠ 0, 𝛼 ∈ ℝ}
B.	{(−4, 2, 1)\|𝛼 ≠ 0, 𝛼∈ℝ}
C.	\(\left\{ {\alpha \left( {\sqrt 2 0,\;1} \right){\rm{\|}}\alpha \; \ne \;0,\;\alpha \in } \mathbb{R} \right\}\)
D.	\($\left\{ {\alpha \left( { - \sqrt 2 ,\;0,\;1} \right)\|\alpha \; \ne \;0,\;\alpha \epsilon \mathbb{R} } \right\}\;$\)
Answer» C. \(\left\{ {\alpha \left( {\sqrt 2 0,\;1} \right){\rm{\|}}\alpha \; \ne \;0,\;\alpha \in } \mathbb{R} \right\}\)

In the given matrix \(\left[ {\begin{array}{*{20}{c}} 1&{ - 1}&2\\ 0&1&0\\ 1&2&1 \end{array}} \right]\), one of the eigenvalues is 1. The eigenvectors corresponding to the eigenvalue 1 are

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