In the following reaction, \[x\] will be \[_{29}C{{u}^{64}}{{\to }_{28}}N{{i}^{64}}+x\]

In the following reaction, \[x\] will be \[_{29}C{{u}^{64}}{{\to }_{

1.	In the following reaction, \[x\] will be \[_{29}C{{u}^{64}}{{\to }_{28}}N{{i}^{64}}+x\]
A.	A proton
B.	An electron
C.	A neutron
D.	A positron
Answer» E.

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In the following reaction, \[x\] will be \[_{29}C{{u}^{64}}{{\to }_{28}}N{{i}^{64}}+x\]

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