MCQOPTIONS
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| 1. |
In the far field diffraction pattern of a single slit under polychromatic illumination, the first minimum with the wavelength \[{{\lambda }_{1}}\] is found to be coincident with the third maximum at \[{{\lambda }_{2}}\]. So |
| A. | \[3{{\lambda }_{1}}=0.3{{\lambda }_{2}}\] |
| B. | \[3{{\lambda }_{1}}={{\lambda }_{2}}\] |
| C. | \[{{\lambda }_{1}}=3.5{{\lambda }_{2}}\] |
| D. | \[0.3{{\lambda }_{1}}=3{{\lambda }_{2}}\] |
| Answer» D. \[0.3{{\lambda }_{1}}=3{{\lambda }_{2}}\] | |