MCQOPTIONS
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| 1. |
In the Bohr's model of hydrogen-like atom the force between the nucleus and the electron is modified as \[F=\frac{{{e}^{2}}}{4\pi {{\varepsilon }_{0}}}\left( \frac{1}{{{r}^{2}}}+\frac{\beta }{{{r}^{3}}} \right),\] where \[\beta \] is a constant. For this atom, the radius of the nth orbit in terms of the Bohr radius \[\left( {{a}_{0}}=\frac{{{\varepsilon }_{0}}{{h}^{2}}}{m\pi {{e}^{2}}} \right)\] is: |
| A. | \[{{r}_{n}}={{a}_{0}}n-\beta \] |
| B. | \[{{r}_{n}}={{a}_{0}}{{n}^{2}}+\beta \] |
| C. | \[{{r}_{n}}={{a}_{0}}{{n}^{2}}-\beta \] |
| D. | \[{{r}_{n}}={{a}_{0}}n+\beta \] |
| Answer» D. \[{{r}_{n}}={{a}_{0}}n+\beta \] | |