MCQOPTIONS
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| 1. |
In TE of propagation, HZ must obey the below equation for wave propagation in the region of presence of dielectric: |
| A. | (∂<sup>2</sup>/∂x<sup>2</sup> + kc<sup>2</sup>) hZ(x,y)=0 |
| B. | (∂<sup>2</sup>/∂x<sup>2</sup>– h<sup>2</sup>)hZ(x,y)=0 |
| C. | (∂<sup>2</sup>/∂x<sup>2</sup> – Kc<sup>2</sup>)hZ(x,y)=0 |
| D. | (∂<sup>2</sup>/∂x<sup>2</sup> +h<sup>2</sup>)hZ(x,y)=0 |
| Answer» B. (‚Äö√Ñ√∂‚àö‚Ć‚àö√°<sup>2</sup>/‚Äö√Ñ√∂‚àö‚Ć‚àö√°x<sup>2</sup>‚Äö√Ñ√∂‚àö√ë‚àö¬® h<sup>2</sup>)hZ(x,y)=0 | |