In Rutherford's experiment, the number of $$\alpha $$- particles scattered through an angle of $$60{}^\circ $$by a silver foil is 200 per minute. When the silver foil is replaced by a copper foil of the same thickness, the number of $$\alpha $$-particles scattered through an angle of $$60{}^\circ $$ per minute is:

Question

TuteeHUB · Accepted Answer

$$200\times \frac{{{Z}_{Cu}}}{{{Z}_{Ag}}}$$

TuteeHUB · Answer

$$\frac{200\times {{Z}_{Cu}}}{{{Z}_{Ag}}}$$

TuteeHUB · Answer

$$200\times {{\left( \frac{{{Z}_{Cu}}}{{{Z}_{Ag}}} \right)}^{2}}$$

TuteeHUB · Answer

$$200\times {{\left( \frac{{{Z}_{Ag}}}{{{Z}_{Cu}}} \right)}^{2}}$$

1.	In Rutherford's experiment, the number of \[\alpha \]- particles scattered through an angle of \[60{}^\circ \]by a silver foil is 200 per minute. When the silver foil is replaced by a copper foil of the same thickness, the number of \[\alpha \]-particles scattered through an angle of \[60{}^\circ \] per minute is:
A.	\[\frac{200\times {{Z}_{Cu}}}{{{Z}_{Ag}}}\]
B.	\[200\times {{\left( \frac{{{Z}_{Cu}}}{{{Z}_{Ag}}} \right)}^{2}}\]
C.	\[200\times \frac{{{Z}_{Cu}}}{{{Z}_{Ag}}}\]
D.	\[200\times {{\left( \frac{{{Z}_{Ag}}}{{{Z}_{Cu}}} \right)}^{2}}\]
Answer» C. \[200\times \frac{{{Z}_{Cu}}}{{{Z}_{Ag}}}\]

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