In order to determine the e.m.f. of a storage battery it was connected in series with a standard cell (both are adding) in a certain circuit and a current $${{I}_{1}}$$ was obtained. When polarity of the standard cell is reversed, a current $${{I}_{2}}$$ was obtained in the same direction as that of $${{I}_{1}}$$ what is the e.m.f. $${{\varepsilon }_{1}}$$ of the storage battery? The e.m.f. of the standard cell is$${{\varepsilon }_{2}}$$.

Question

TuteeHUB · Accepted Answer

$${{\varepsilon }_{1}}=\frac{{{I}_{1}}+{{I}_{2}}}{{{I}_{2}}-{{I}_{1}}}{{\varepsilon }_{2}}$$

TuteeHUB · Answer

$${{\varepsilon }_{1}}=\frac{{{I}_{1}}+{{I}_{2}}}{{{I}_{1}}-{{I}_{2}}}{{\varepsilon }_{2}}$$

TuteeHUB · Answer

$${{\varepsilon }_{1}}=\frac{{{I}_{1}}-{{I}_{2}}}{{{I}_{1}}+{{I}_{2}}}{{\varepsilon }_{2}}$$

TuteeHUB · Answer

$${{\varepsilon }_{1}}=\frac{{{I}_{2}}-{{I}_{1}}}{{{I}_{1}}+{{I}_{2}}}{{\varepsilon }_{2}}$$

1.	In order to determine the e.m.f. of a storage battery it was connected in series with a standard cell (both are adding) in a certain circuit and a current \[{{I}_{1}}\] was obtained. When polarity of the standard cell is reversed, a current \[{{I}_{2}}\] was obtained in the same direction as that of \[{{I}_{1}}\] what is the e.m.f. \[{{\varepsilon }_{1}}\] of the storage battery? The e.m.f. of the standard cell is\[{{\varepsilon }_{2}}\].
A.	\[{{\varepsilon }_{1}}=\frac{{{I}_{1}}+{{I}_{2}}}{{{I}_{1}}-{{I}_{2}}}{{\varepsilon }_{2}}\]
B.	\[{{\varepsilon }_{1}}=\frac{{{I}_{1}}+{{I}_{2}}}{{{I}_{2}}-{{I}_{1}}}{{\varepsilon }_{2}}\]
C.	\[{{\varepsilon }_{1}}=\frac{{{I}_{1}}-{{I}_{2}}}{{{I}_{1}}+{{I}_{2}}}{{\varepsilon }_{2}}\]
D.	\[{{\varepsilon }_{1}}=\frac{{{I}_{2}}-{{I}_{1}}}{{{I}_{1}}+{{I}_{2}}}{{\varepsilon }_{2}}\]
Answer» B. \[{{\varepsilon }_{1}}=\frac{{{I}_{1}}+{{I}_{2}}}{{{I}_{2}}-{{I}_{1}}}{{\varepsilon }_{2}}\]

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