In Newton's experiment of cooling, the water equivalent of two similar calorimeters is 10 gm each. They are filled with 350 gm of water and 300 gm of a liquid (equal volumes) separately. The time taken by water and liquid to cool from $${{70}^{o}}C$$ to $${{60}^{o}}C$$ is 3 min and 95 sec respectively. The specific heat of the liquid will be

Question

TuteeHUB · Accepted Answer

$$0.8\,Cal\text{/}gm\times {}^\circ C$$

TuteeHUB · Answer

$$0.3\,Cal\text{/}gm\times {}^\circ C$$

TuteeHUB · Answer

$$0.6\,Cal\text{/}gm\times {}^\circ C$$

TuteeHUB · Answer

$$0.6\,Cal\text{/}gm\times {}^\circ C$$

1.	In Newton's experiment of cooling, the water equivalent of two similar calorimeters is 10 gm each. They are filled with 350 gm of water and 300 gm of a liquid (equal volumes) separately. The time taken by water and liquid to cool from \[{{70}^{o}}C\] to \[{{60}^{o}}C\] is 3 min and 95 sec respectively. The specific heat of the liquid will be
A.	\[0.3\,Cal\text{/}gm\times {}^\circ C\]
B.	\[0.6\,Cal\text{/}gm\times {}^\circ C\]
C.	\[0.6\,Cal\text{/}gm\times {}^\circ C\]
D.	\[0.8\,Cal\text{/}gm\times {}^\circ C\]
Answer» D. \[0.8\,Cal\text{/}gm\times {}^\circ C\]

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