In Milikan's oil drop experiment, a charged drop falls with terminal v – McqOptions

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1.	In Milikan's oil drop experiment, a charged drop falls with terminal velocity V. If an electric field E is applied in vertically upward direction then it starts moving in upward direction with terminal velocity 2V. If magnitude of electric field is decreased to \[\frac{E}{2}\], then terminal velocity will become [CBSE PMT 1999]
A.	\[\frac{V}{2}\]
B.	V
C.	\[\frac{3V}{2}\]
D.	2V
Answer» D. 2V

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