In Milikan's oil drop experiment, a charged drop falls with terminal velocity V. If an electric field E is applied in vertically upward direction then it starts moving in upward direction with terminal velocity 2V. If magnitude of electric field is decreased to \[\frac{E}{2}\], then terminal velocity will become [CBSE PMT 1999]

• A.            \[\frac{V}{2}\]          
• B.            V
• C.            \[\frac{3V}{2}\]        
• D.            2V