In methyl alcohol solution, bromine reacts with ethylene to yield \[BrC{{H}_{2}}C{{H}_{2}}OC{{H}_{3}}\] in addition to 1, 2-dibromoethane because [Pb. PMT 1998]

The methyl alcohol solvates the bromine

The ion formed initially may react with \[B{{r}^{-}}\] or \[C{{H}_{3}}OH\]

The reaction follows Markownikoff's rule

This is a free-radical mechanism

In methyl alcohol solution, bromine reacts with ethylene to yield \[Br

1.	In methyl alcohol solution, bromine reacts with ethylene to yield \[BrC{{H}_{2}}C{{H}_{2}}OC{{H}_{3}}\] in addition to 1, 2-dibromoethane because [Pb. PMT 1998]
A.	The ion formed initially may react with \[B{{r}^{-}}\] or \[C{{H}_{3}}OH\]
B.	The methyl alcohol solvates the bromine
C.	The reaction follows Markownikoff's rule
D.	This is a free-radical mechanism
Answer» B. The methyl alcohol solvates the bromine

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In methyl alcohol solution, bromine reacts with ethylene to yield \[BrC{{H}_{2}}C{{H}_{2}}OC{{H}_{3}}\] in addition to 1, 2-dibromoethane because [Pb. PMT 1998]

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